QuestionFind $\cos \theta$ if $\sin \theta=\frac{12}{13}$ and $\theta$ is in quadrant II.

Studdy Solution
However, we know that $\theta$ is in quadrant II, and in this quadrant, cosine is negative. Therefore, we must take the negative root$$\cos \theta = -\frac{5}{13}$$So, the exact value of $\cos \theta$ is $-\frac{5}{13}$.