Question Find the equation of a circle with center at $(-3, 6)$ given that the line $3x - y - 5 = 0$ is tangent to the circle.

Studdy Solution
The equation of the circle in standard form is:
$$(x + 3)^2 + (y - 6)^2 = 40$$
This is the final equation of the circle with center $(-3,6)$ that is tangent to the line $3x - y - 5 = 0$.