QuestionFind the derivative of the function. $$\begin{array}{l} f(x)=7 x^{2} \ln (6 x) \\ f^{\prime}(x)=\square \end{array}$$ Need Help? Watch It

Studdy Solution
Combine the results using the product rule:
$$f'(x) = u'(x)v(x) + u(x)v'(x)$$ $$f'(x) = (14x)(\ln(6x)) + (7x^2)\left(\frac{1}{x}\right)$$ $$f'(x) = 14x \ln(6x) + 7x$$
The derivative of the function is:
$$f'(x) = 14x \ln(6x) + 7x$$