QuestionFind the derivative of the following function. $$\begin{array}{l} y=-8^{8 x^{2}-5} \\ \frac{d y}{d x}=\square \end{array}$$

Studdy Solution
Substitute back $u = 8x^2 - 5$ into the expression:
$$\frac{dy}{dx} = -\ln(8) \cdot 8^{8x^2 - 5} \cdot 16x$$
Simplify the expression:
$$\frac{dy}{dx} = -16x \ln(8) \cdot 8^{8x^2 - 5}$$
The derivative of the function is:
$$\frac{dy}{dx} = -16x \ln(8) \cdot 8^{8x^2 - 5}$$