QuestionFind the complex zeros of $f(x)=-2x^2+16x-23$ and graph the function, labeling the intercepts.

Studdy Solution
Now we can graph the function. Plot the vertex and the x-intercepts, and draw a smooth curve through these points. The curve opens downwards because the coefficient of $x^2$ is negative.
The x-intercepts are the points $(4 -2\sqrt{2},0)$ and $(4 +2\sqrt{2},0)$, and the vertex is the point $(4, -23)$.