Math  /  Trigonometry

Question Find one solution for the equation sec(3β+12)=csc(2β+3)\sec(3\beta + 12^\circ) = \csc(2\beta + 3^\circ). Simplify the answer β\beta.

Studdy Solution
Since we are assuming all angles are acute, the second solution is not valid. So the only solution is β=15\beta=15^{\circ}.
So, β=15\beta=15^{\circ}.

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