QuestionFind $C$ and $D$ so that the solution set to the system is $\{(2,2)\}$ . $\begin{array}{c} C x+5 y=8 \\ -5 x+D y=-18 \end{array}$
Part 1 of 2 $C=$ $\square$
Part 2 of 2 $D=$ $\square$

Studdy Solution
Solve for $D$ :
Add 10 to both sides:
$2D = -18 + 10$
$2D = -8$
Divide both sides by 2:
$D = -4$
The values are: $C = -1$ $D = -4$

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