QuestionSolve for real $x$ in the equation $x^{2}-10x+23=23$ by completing the square. Find $x_{1}$ and $x_{2}$ with $x_{1}<x_{2}$.

Studdy Solution
olving the second equation for x gives us the second solution.
$$x=10$$So, the solutions to the equation are $x_{1}=0$ and $x_{2}=10$ with $x_{1}<x_{2}$.