Math  /  Algebra

QuestionEquations Points: 0 of 1
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1 , and roots of 26,2+62-\sqrt{6}, 2+\sqrt{6}, and 7i7-i.
The polynomial function is P(x)=\mathrm{P}(\mathrm{x})= \square (Simplify your answer.) View an example Get more help

Studdy Solution
Multiply the two quadratic factors to form the polynomial: (x24x2)(x214x+50) (x^2 - 4x - 2)(x^2 - 14x + 50)
Expand the expression: =x2(x214x+50)4x(x214x+50)2(x214x+50) = x^2(x^2 - 14x + 50) - 4x(x^2 - 14x + 50) - 2(x^2 - 14x + 50)
=x414x3+50x24x3+56x2200x2x2+28x100 = x^4 - 14x^3 + 50x^2 - 4x^3 + 56x^2 - 200x - 2x^2 + 28x - 100
Combine like terms: =x418x3+104x2172x100 = x^4 - 18x^3 + 104x^2 - 172x - 100
The polynomial function is:
P(x)=x418x3+104x2172x100 \mathrm{P}(x) = x^4 - 18x^3 + 104x^2 - 172x - 100

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