QuestionFind a domain where the function $f(x)=x^{2}-9$ is one-to-one and non-decreasing, then find its inverse.

Studdy Solution
This is the inverse function. We denote the inverse function as $f^{-1}(x)$.
$$f^{-1}(x) = \sqrt{x +}$$The domain where $f$ is one-to-one and non-decreasing is $[0, +\infty)$, and the inverse of $f$ restricted to that domain is $f^{-1}(x) = \sqrt{x +}$.