Math  /  Algebra

Questionfield R\mathbb{R}. Find the following: the sum: 6 田 5=-5= \square the scalar multiple: 7 ■ 6=6= \square the zero vector: 0V=\underline{0}_{V}= \square the additive inverse of xx : 日 x=x= \square
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Studdy Solution
Find the additive inverse x\boxminus x such that x(x)=0V x \boxplus (\boxminus x) = \underline{0}_{V} .
Using the vector addition definition:
x(x)=x+(x)+2=2 x \boxplus (\boxminus x) = x + (\boxminus x) + 2 = -2
Solving for x\boxminus x:
x+(x)+2=2 x + (\boxminus x) + 2 = -2 x=22x \boxminus x = -2 - 2 - x x=x4 \boxminus x = -x - 4
The additive inverse is:
x4 \boxed{-x - 4}

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