Math  /  Algebra

QuestionFactor the expression 4sin2θ4 - \sin^2 \theta completely over the integers.

Studdy Solution
Now, we can rewrite the expression using the difference of squares formula, which states that a2b2=(a+b)(ab)a^2 - b^2 = (a+b)(a-b). In this case, a=3a = \sqrt{3} and b=cosθb = \cos\theta.
3+cos2θ=(3+cosθ)(3cosθ)3+\cos^2\theta = (\sqrt{3}+\cos\theta)(\sqrt{3}-\cos\theta)So, the expression 4sin2θ4-\sin^2\theta factors over the integers to (3+cosθ)(3cosθ)(\sqrt{3}+\cos\theta)(\sqrt{3}-\cos\theta).

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord