QuestionExpress the given quantity as a single logarithm $$6 \log _{7}(4)-\log _{7}(8)=\log _{7}($$

Studdy Solution
Calculate $\frac{4096}{8}$:
$$\frac{4096}{8} = 512$$
So,
$$\log_{7}\left(\frac{4096}{8}\right) = \log_{7}(512)$$
The expression simplifies to:
$$\log_{7}(512)$$