QuestionEXAMPLE: Determine the total number of ions that will be present in the precipitate formed when a solution with 20.00 grams of barium nitrate reacts with a solution containing excess potassium phosphate.

Studdy Solution
Calculate the total number of ions in the precipitate.
Barium phosphate $(\text{Ba}_3(\text{PO}_4)_2)$ dissociates into 3 barium ions $(\text{Ba}^{2+})$ and 2 phosphate ions $(\text{PO}_4^{3-})$.
Total ions per formula unit of barium phosphate:
$$3 + 2 = 5 \text{ ions}$$
Calculate the total number of ions:
$$\text{Total ions} = 0.0255 \text{ mol} \times 5 \text{ ions/mol} \times 6.022 \times 10^{23} \text{ ions/mol}$$
$$\text{Total ions} \approx 7.68 \times 10^{22} \text{ ions}$$