Math  /  Algebra

QuestionExample 4: a 3.34 g sample of a hydrate has the formula SrS2O3×H2O\mathrm{SrS}_{2} \mathrm{O}_{3} \cdot \times \mathrm{H}_{2} \mathrm{O}, and contains 2.30 g of SrS2O3\mathrm{SrS}_{2} \mathrm{O}_{3}. Find the value of xx

Studdy Solution
Find the ratio of moles of water to moles of SrS2O3\mathrm{SrS}_{2} \mathrm{O}_{3} to determine xx.
x=Moles of waterMoles of SrS2O3 x = \frac{\text{Moles of water}}{\text{Moles of } \mathrm{SrS}_{2} \mathrm{O}_{3}}
Substitute the values from the previous steps to find xx.
Solution: Assuming the molar mass MM of SrS2O3\mathrm{SrS}_{2} \mathrm{O}_{3} is known, substitute the values to find xx.

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