Question Evaluate the integral of $\tan^3(x)\sec^6(x)$ and include the constant of integration.

Studdy Solution
Write the final answer.
The evaluated integral is: $$\int \tan^{3}(x) \sec^{6}(x) dx = \frac{\sec^{9}(x)}{9} - \frac{\sec^{7}(x)}{7} + C$$