QuestionEvaluate the given definite integral. $$\int_{2}^{4}\left(3 x^{2}-\frac{x^{3}}{5}\right) d x$$ $\int_{2}^{4}\left(3 x^{2}-\frac{x^{3}}{5}\right) d x=$ $\square$ (Simplify your answer.)

Studdy Solution
Subtract the value found in step 3 from the value found in step 2 to find the definite integral.
$$\int_{2}^{4}\left(3 x^{2}-\frac{x^{3}}{5}\right) d x = F(4) - F(2)$$ $$= 51.2 - 7.2$$ $$= 44$$
The value of the definite integral is:
$$\boxed{44}$$