QuestionEvaluate $\left(\frac{h}{f}\right)(1)$ for the functions $f(x)=3x$, $g(x)=|x-4|$, and $h(x)=\frac{1}{x-7}$.

Studdy Solution
implify the expression to find the value of $\left(\frac{h}{f}\right)(1)$.
$$\left(\frac{h}{f}\right)(1) = \frac{-\frac{1}{6}}{3} = -\frac{1}{18}$$So, $\left(\frac{h}{f}\right)(1) = -\frac{1}{18}$.