Math  /  Calculus

QuestionEvaluate the following integral using the Fundámental Theorem of Calculus. 5π/25π/2(cosx4)dx\int_{-5 \pi / 2}^{5 \pi / 2}(\cos x-4) d x 5π/25π/2(cosx4)dx=\int_{-5 \pi / 2}^{5 \pi / 2}(\cos x-4) d x=\square \square (Type an exact answer.)

Studdy Solution
Calculate the difference F(5π/2)F(5π/2)F(5\pi/2) - F(-5\pi/2):
F(5π/2)F(5π/2)=(110π)(1+10π) F(5\pi/2) - F(-5\pi/2) = (1 - 10\pi) - (-1 + 10\pi) =110π+110π = 1 - 10\pi + 1 - 10\pi =220π = 2 - 20\pi
The exact value of the integral is:
220π \boxed{2 - 20\pi}

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