QuestionEvaluate the following antiderivatives. a) $\int 8 \cos (x)+\sec ^{2}(x) d x=\square+C$ b) $\int \frac{x^{5}+6 \sqrt{x}}{x^{3}} d x=\square+C$

Studdy Solution
Summarize the solutions for both parts:
a) $\int 8 \cos(x) + \sec^2(x) \, dx = 8 \sin(x) + \tan(x) + C$
b) $\int \frac{x^5 + 6 \sqrt{x}}{x^3} \, dx = \frac{x^3}{3} - 4 x^{-3/2} + C$