Math  /  Calculus

QuestionEvaluate the following antiderivatives. a) 8cos(x)+sec2(x)dx=+C\int 8 \cos (x)+\sec ^{2}(x) d x=\square+C

Studdy Solution
Combine the results of the two integrals and add the constant of integration CC:
(8cos(x)+sec2(x))dx=8sin(x)+tan(x)+C\int (8 \cos(x) + \sec^2(x)) \, dx = 8 \sin(x) + \tan(x) + C
The antiderivative is 8sin(x)+tan(x)+C8 \sin(x) + \tan(x) + C.

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