Math  /  Calculus

QuestionEnter your answer as a fraction or as a number rounded to three decimal places. Find the area bounded by the graphs of y=x2y=x^{2} and y=32x2y=32-x^{2} for 0x90 \leq x \leq 9. Area = \square

Studdy Solution
Calculate the definite integrals:
Area=(32×432×0)(23(4)323(0)3) \text{Area} = (32 \times 4 - 32 \times 0) - \left( \frac{2}{3}(4)^3 - \frac{2}{3}(0)^3 \right)
Area=12823(64) \text{Area} = 128 - \frac{2}{3}(64)
Area=1281283 \text{Area} = 128 - \frac{128}{3}
Area=38431283 \text{Area} = \frac{384}{3} - \frac{128}{3}
Area=2563 \text{Area} = \frac{256}{3}
The area bounded by the graphs is:
2563 \boxed{\frac{256}{3}}

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