QuestionE.g. Solve the following triangles: a. b. $$\begin{array}{l} \angle P=180^{\circ}-90^{\circ}-37^{\circ}=53^{\circ} \\ \cos 37^{\circ}-1 \frac{19}{q} \\ \tan 37^{\circ}=\frac{r}{19} \\ q=\frac{19}{\cos 37^{\circ}} \\ r=19 \tan 37^{\circ} \\ q \doteq 23.8 \\ r \doteq 14.3 \end{array}$$ $$\therefore \angle P=53^{\circ}, q \doteq 23.8 \mathrm{~cm}, r \equiv 19.3 \mathrm{~cm}$$