Math  /  Calculus

QuestionDuring a certain 15 -hour period, the temperature at time tt (measured in hours from the start of the period) was T(t)=41+6t13t2T(t)=41+6 t-\frac{1}{3} t^{2} degrees. What was the average temperature during that period?
The average temperature was \square { }^{\circ}

Studdy Solution
The average temperature during that 15-hour period was 61\bf{61} degrees!

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