QuestionDifferentiate $y=\frac{1}{\sqrt{a+x^{2}}}$ with respect to $x$.

Studdy Solution
implify the expression to get the final derivative.
$$\frac{dy}{dx} = -x(a+x^{2})^{-\frac{3}{2}}$$So, the derivative of $y=\frac{1}{\sqrt{a+x^{2}}}$ with respect to $x$ is $-x(a+x^{2})^{-\frac{3}{2}}$.