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Math  /  Algebra

QuestionDetermine the range of the function y=x−2y=\sqrt{x-2}. {y∈R;y≥0}\{y \in R ; y \geq 0\} {y∈R}\{y \in R\} {x∈R;x≥−2}\{x \in R ; x \geq-2\} {x∈R}\{x \in R\}
Question 2 (1 point)

Studdy Solution
The range of the function y=x−2y = \sqrt{x - 2} is {y∈R;y≥0}\{y \in \mathbb{R} ; y \geq 0\}.

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