QuestionDetermine the number of terms $n$ in the geometr 3) $4+12+36+108 \ldots, S_{n}=39364$

Studdy Solution
Solve for $n$ by recognizing that $19683$ is a power of 3. Calculate:
$$3^9 = 19683$$
Thus, $n = 9$.
The number of terms $n$ is:
$$\boxed{9}$$