Math  /  Algebra

QuestionDetermine if the function h(x)=x2+1h(x)=x^{2}+1 is even, odd, or neither using algebraic methods.

Studdy Solution
Now we compare h(x)h(-x) with h(x)h(x). If they are equal, then the function is even. If h(x)h(-x) is the negation of h(x)h(x), then the function is odd. If neither of these conditions are met, then the function is neither even nor odd.
From the above steps, we see that h(x)=h(x)h(-x) = h(x), which means the function is even.
The function h(x)=x2+1h(x)=x^{2}+1 is even.

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