Math  /  Algebra

QuestionDescribe the end behavior of the graphs of the function. f(x)=4(2)x2f(x)=-4(2)^{x}-2
As x,f(x)x \rightarrow-\infty, f(x) \rightarrow \square As x,f(x)x \rightarrow \infty, f(x) \rightarrow \square

Studdy Solution
To determine the end behavior of f(x) f(x) as x x \rightarrow \infty :
f(x)=4(2)x2 f(x) = -4(2)^x - 2
Since (2)x (2)^x \rightarrow \infty , the term 4(2)x -4(2)^x \rightarrow -\infty . Therefore,
f(x) f(x) \rightarrow -\infty
As x,f(x) x \rightarrow \infty, f(x) \rightarrow -\infty .
The end behavior of the function is:
As x,f(x)2 x \rightarrow -\infty, f(x) \rightarrow -2 .
As x,f(x) x \rightarrow \infty, f(x) \rightarrow -\infty .

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord