QuestionDado $\cos \alpha=\frac{\sqrt{3}}{2}$, calcular $\operatorname{Sen} 2 \alpha, \operatorname{Cos} 2 \alpha, \operatorname{Tg} 2 \alpha$

Studdy Solution
Resultados finales:
1. Si $\operatorname{Sen} \alpha = \frac{1}{2}$: - $\operatorname{Sen} 2\alpha = \frac{\sqrt{3}}{2}$ - $\operatorname{Cos} 2\alpha = \frac{1}{2}$ - $\operatorname{Tg} 2\alpha = \sqrt{3}$
2. Si $\operatorname{Sen} \alpha = -\frac{1}{2}$: - $\operatorname{Sen} 2\alpha = -\frac{\sqrt{3}}{2}$ - $\operatorname{Cos} 2\alpha = \frac{1}{2}$ - $\operatorname{Tg} 2\alpha = -\sqrt{3}$