Math  /  Algebra

QuestionConsider the following vectors: a=[1231]b=[1412]c=[22101]\mathbf{a}=\left[\begin{array}{c} 1 \\ 2 \\ -3 \\ -1 \end{array}\right] \quad \mathbf{b}=\left[\begin{array}{c} 1 \\ 4 \\ -1 \\ -2 \end{array}\right] \mathbf{c}=\left[\begin{array}{c} 2 \\ -2 \\ -10 \\ -1 \end{array}\right]
For each of the following vectors, determine whether it is in span{a,b,c}\operatorname{span}\{\mathbf{a}, \mathbf{b}, \mathbf{c}\}. If so, express it as a linear combination using a,ba, b, and cc as the names of the vectors above. v1=[24120]\mathbf{v}_{1}=\left[\begin{array}{c}2 \\ -4 \\ -12 \\ 0\end{array}\right] < Select an answer > v2=[2824]\mathbf{v}_{2}=\left[\begin{array}{c}-2 \\ -8 \\ 2 \\ 4\end{array}\right] \quad Select an answer > v3=[10266]\mathbf{v}_{3}=\left[\begin{array}{c}-10 \\ 2 \\ 6 \\ -6\end{array}\right] < Select an answer >

Studdy Solution
Determine if v3\mathbf{v}_3 is in the span and express it as a linear combination:
Since a solution exists, v3\mathbf{v}_3 is in span{a,b,c}\operatorname{span}\{\mathbf{a}, \mathbf{b}, \mathbf{c}\}. Express v3\mathbf{v}_3 as: v3=2a+1b4c\mathbf{v}_3 = -2\mathbf{a} + 1\mathbf{b} - 4\mathbf{c}
The results are: - v1\mathbf{v}_1 is in the span and can be expressed as 0a+0b+1c0\mathbf{a} + 0\mathbf{b} + 1\mathbf{c}. - v2\mathbf{v}_2 is not in the span. - v3\mathbf{v}_3 is in the span and can be expressed as 2a+1b4c-2\mathbf{a} + 1\mathbf{b} - 4\mathbf{c}.

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