QuestionConsider the following lines. Line 1: $3 x-4 y=12$ Line 2: a line perpendicular to $3 x-4 y=12$ that contains the point $(3,-4)$ Write the equation of Line 1 in slope-intercept form. $\square$ Find the slope of Line 1. $\square$ Find the slope of Line 2. $\square$ Find the equation of Line 2 in point-slope form using the point $(3,-4)$ . $\square$ Find the equation of Line 2 in the form $A x+B y=C$ . $\square$ Need Help? Read It

Studdy Solution
Convert the equation of Line 2 from point-slope form to standard form $Ax + By = C$ .
Start with:
$y + 4 = -\frac{4}{3}(x - 3)$
Distribute the slope:
$y + 4 = -\frac{4}{3}x + 4$
Subtract 4 from both sides:
$y = -\frac{4}{3}x$
Multiply every term by 3 to eliminate the fraction:
$3y = -4x$
Rearrange to standard form:
$4x + 3y = 0$

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