Math  /  Algebra

QuestionCondense the expression to a single logarithm. Write fractional exponents as radicals. Assume that all variables represent positive numbers. 6log3(x+6)log3(x4)log3(x5)=6 \log _{3}(x+6)-\log _{3}(x-4)-\log _{3}(x-5)=

Studdy Solution
Since there are no fractional exponents in the expression, there is no need to convert any terms to radicals. The expression is already in its simplest form as a single logarithm.
The condensed expression is:
log3((x+6)6(x4)(x5)) \log_{3}\left(\frac{(x+6)^6}{(x-4)(x-5)}\right)

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