QuestionCompute the given integral. $$\int \frac{1}{\sqrt{49-x^{2}}} d x=\square+C$$

Studdy Solution
Substitute $a = 7$ into the identity:
$\int \frac{1}{\sqrt{49-x^{2}}} \, dx = \arcsin\left(\frac{x}{7}\right) + C$
The solution to the integral is:
$\boxed{\arcsin\left(\frac{x}{7}\right) + C}$