QuestionComplete the proof that $\triangle E F G \cong \triangle E G F$. \begin{tabular}{|l|l|l|} \hline & Statement & Reason \\ \hline 1 & $\angle F \cong \angle G$ & Given \\ 2 & $\overline{F G} \cong \overline{F G}$ & Reflexive Property of Congruence \\ 3 & $\triangle E F G \cong \triangle E G F$ & \\ \hline \end{tabular}

Studdy Solution
Use the given information and properties to complete the proof:
According to the ASA Congruence Postulate, if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.
Given: - $\angle F \cong \angle G$ (Given) - $\overline{FG} \cong \overline{FG}$ (Reflexive Property of Congruence)
Therefore, by the ASA Congruence Postulate:
$\triangle EFG \cong \triangle EGF$
The proof is complete:
$\boxed{\triangle EFG \cong \triangle EGF}$