Math  /  Data & Statistics

Question\begin{tabular}{|c|c|c|c|c|} \hline Cavim & Contre dectuse x1x_{1} & Ettrect ω1\omega_{1} & \begin{tabular}{l} ENoctil Cumule \\ * mation ω1()\omega_{1}(-) \end{tabular} & \\ \hline .5-161.5 & 160,5 & 7 & 7 & 307 \\ \hline 510,55-10,5 & 162.5 & 4 & 11 & 300 \\ \hline (5-155,5 & 164.5 & 10 & 21 & 296 \\ \hline - 5 - 167,5 & 265.5 & 23 & 44 & 286 \\ \hline s-169,5 & 1085 & 19 & H3 & 263 \\ \hline P- uxes & 17e2 & 00 & H2 & en \\ \hline 512035-1203 & (172 & 45 & 97 & 2es \\ \hline 5175,55-175,5 & 174,5 & 411 & 205 & 150 \\ \hline 5177,55-177,5 & 176,5 & 35 & 200 & 102 \\ \hline 5132.55-132.5 & 178,5 & 31 & 271 & 67 \\ \hline -181,5 & 180,5 & 16 & 287 & 96 \\ \hline 283,5-283,5 & 182,5 & 9 & 296 & 20 \\ \hline - 185,5 & 184,5 & 5 & 301 & 11 \\ \hline - 187.5 & 186,5 & 3 & 304 & 6 \\ \hline - 109.5 & 188.5 & 1 & 305 & 3 \\ \hline 202,5-202,5 & 100, 5 & 2 & 307 & 2 \\ \hline \multicolumn{5}{|l|}{EN=307} \\ \hline \end{tabular} 76,75dme76,75^{\mathrm{dme}} valeur ( 25%25 \% de 307): 170,5 cm170,5 \mathrm{~cm} 153,5ème valeur ( 50%50 \% de 307) : 172,5 cm172,5 \mathrm{~cm} 230,25eˋme 230,25^{\text {ème }} valeur ( 75%75 \% de 307 ) : 176,5 cm176,5 \mathrm{~cm}
Méthode d'interpolation : Tenir compte du rang recherche Q1=169,5+(307/4)6339×2=170,2 cmQ3=175,5+(307×34)20535×2=176,9 cm\begin{array}{l} Q_{1}=169,5+\frac{(307 / 4)-63}{39} \times 2=170,2 \mathrm{~cm} \\ Q_{3}=175,5+\frac{\left(307 \times \frac{3}{4}\right)-205}{35} \times 2=176,9 \mathrm{~cm} \end{array}
Possibilité de déterminer les quartiles graphiquement

Studdy Solution
Appliquer la formule d'interpolation pour Q3Q_3:
Q3=175.5+(230.2520535)×2 Q_3 = 175.5 + \left(\frac{230.25 - 205}{35}\right) \times 2
Q3=175.5+(25.2535)×2 Q_3 = 175.5 + \left(\frac{25.25}{35}\right) \times 2
Q3=175.5+1.443 Q_3 = 175.5 + 1.443
Q3176.9cm Q_3 \approx 176.9 \, \text{cm}
Les quartiles sont:
Q1170.2cm Q_1 \approx 170.2 \, \text{cm} Q3176.9cm Q_3 \approx 176.9 \, \text{cm}

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