Math  /  Data & Statistics

QuestionCans of soda vary slightly in weight. Given below are the measured weights of seven cans, in pounds. Find the mean and median of these weights. Which, if any, of these weights would be considered an outlier? What are the mean and median weights if the outlier is excluded? 0.81590.81920.81630.81760.79070.81440.8125\begin{array}{lllllll} 0.8159 & 0.8192 & 0.8163 & 0.8176 & 0.7907 & 0.8144 & 0.8125 \end{array}
Find the mean and median of the weights The mean is \square (Round to five decimal places as needed.)

Studdy Solution
Recalculate the median excluding the outlier:
Order the remaining weights:
0.8125,0.8144,0.8159,0.8163,0.8176,0.8192 0.8125, 0.8144, 0.8159, 0.8163, 0.8176, 0.8192
The median of 6 values is the average of the 3rd and 4th values:
0.8159+0.81632=0.8161 \frac{0.8159 + 0.8163}{2} = 0.8161
The mean excluding the outlier is:
0.816 \boxed{0.816}
The median excluding the outlier is:
0.8161 \boxed{0.8161}

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