QuestionCalculate the de Broglie wavelength of an electron moving at $2.35 \times 10^{6} \mathrm{~m} / \mathrm{s}$.

Studdy Solution
Finally, divide the numerator by the denominator to find the wavelength.
$$\lambda = \frac{.626 \times10^{-34} \, \mathrm{m^2 kg / s}}{2.14 \times10^{-24} \, \mathrm{kg \cdot m/s}} =3.10 \times10^{-10} \, \mathrm{m}$$The de Broglie wavelength of an electron traveling with a speed of $2.35 \times10^{} \, \mathrm{m/s}$ is $3.10 \times10^{-10} \, \mathrm{m}$.