Math  /  Algebra

QuestionCalculate c. log(72)\log (72) d. log(121)\log (121)

Studdy Solution
Use the properties of logarithms to simplify log(121)\log(121):
log(121)=log(112) \log(121) = \log(11^2)
Apply the power rule: log(ab)=blog(a)\log(a^b) = b \cdot \log(a):
log(121)=2log(11) \log(121) = 2 \cdot \log(11)
The expressions for the logarithms are:
log(72)=3log(2)+2log(3) \log(72) = 3 \cdot \log(2) + 2 \cdot \log(3) log(121)=2log(11) \log(121) = 2 \cdot \log(11)

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