Math  /  Data & Statistics

QuestionBookwork code: 2C Calculator not allowed
The journey time from Waterloo to Dartford is always the same. Work out the time that goes in the gap. \begin{tabular}{|l|c|c|c|} \hline Train station & \multicolumn{3}{|c|}{ Time } \\ \hline Waterloo & 17:2517: 25 & 17:4517: 45 & \square \\ \hline Bridge & 17:3117: 31 & 17:5517: 55 & 18:0918: 09 \\ \hline Lewisham & 17:5017: 50 & 18:0018: 00 & 18:1718: 17 \\ \hline Blackheath & 18:0218: 02 & 18:1018: 10 & 18:2918: 29 \\ \hline Dartford & 18:3018: 30 & 18:5018: 50 & 19:1019: 10 \\ \hline \end{tabular}

Studdy Solution
Apply the journey time to the third train:
- Start time at Waterloo for the third train: 18:09 18:09
Add the journey time of 1 hour and 5 minutes 1 \text{ hour and } 5 \text{ minutes} :
18:09+1 hour and 5 minutes=19:14 18:09 + 1 \text{ hour and } 5 \text{ minutes} = 19:14
The time that goes in the gap is:
19:14 \boxed{19:14}

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