Math / GeometryQuestionBDB DBD bisects ∠ABC\angle A B C∠ABC with m∠ABD=(8x−1)∘m \angle A B D=(8 x-1)^{\circ}m∠ABD=(8x−1)∘ and m∠DBC=(6x+5)∘m \angle D B C=(6 x+5)^{\circ}m∠DBC=(6x+5)∘. Find m∠ABDm \angle A B Dm∠ABD.Studdy SolutionCalculate the measure of ∠ABD\angle ABD∠ABDm∠ABD=23∘m \angle ABD =23^\circm∠ABD=23∘So, the measure of ∠ABD\angle ABD∠ABD is 23∘23^\circ23∘. View Full Solution - FreeWas this helpful?
