Questionb) $\tan ^{2} x \sin x-\frac{\sin x}{3}=0$ c) $\cos ^{2} x+\left(\frac{1-\sqrt{2}}{2}\right) \cos x-\frac{\sqrt{2}}{4}=$

Studdy Solution
For $\tan ^{2} x \sin x-\frac{\sin x}{3}=0$, $x = n\pi$, and $x = \frac{\pi}{6} + n\pi$, where $n$ is an integer.
For $\cos ^{2} x+\left(\frac{1-\sqrt{2}}{2}\right) \cos x-\frac{\sqrt{2}}{4}=0$, $x = \frac{\pi}{4} + 2n\pi$, $x = \frac{7\pi}{4} + 2n\pi$, $x = \frac{2\pi}{3} + 2n\pi$, and $x = \frac{4\pi}{3} + 2n\pi$, where $n$ is an integer.