Math  /  Algebra

Questionb Arầtati că numărul a5325\overline{a 5}^{3}-25 se divide cu 100 . 20 a Efectuati: 1(2k)21(2 k)^{2}; in (2k+1)2(2 k+1)^{2}. b Deduceți că un număr natural care dă restul 3 la impărțirea cu 4 nu este pătrat perfect. c Arătați că numărul 111151 nu este pătrat perfect. iin(3k+2)2i i n(3 k+2)^{2}

Studdy Solution
Estimate 111151\sqrt{111151}:
111151333.33\sqrt{111151} \approx 333.33
Check perfect squares:
- 3332=110889333^2 = 110889 - 3342=111556334^2 = 111556
Since 111151 is not equal to either 110889 or 111556, it is not a perfect square.
The solution to the problems is complete.

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