QuestionASSIGNMENT - Calculate the number density of free carriers in silver, assuming that each atom contributes one carrier, the density of silver is $105 x \frac{10^{3} \mathrm{~kg}}{\mathrm{~m}^{3}}$ and the atomic weight is $107 . \mathrm{g} / \mathrm{mol}$.

Studdy Solution
Calculate the number density of free carriers.
$\text{Number density of free carriers} \approx 5.91 \times 10^{28} \, \text{carriers/m}^3$
The number density of free carriers in silver is approximately $5.91 \times 10^{28} \, \text{carriers/m}^3$.