Math  /  Data & Statistics

QuestionAn energy company wants to choose between two regions in a state to install energy-producing wind turbines. A researcher claims that the wind speed in Region AA is less than the wind speed in Region BB. To test the regions, the average wind speed is calculated for 90 days in each region. The mean wind speed in Region A is 14.1 miles per hour. Assume the population standard deviation is 2.8 miles per hour. The mean wind speed in Region B is 15.3 miles per hour. Assume the population standard deviation is 3.2 miles per hour. At α=0.05\alpha=0.05, can the company support the researcher's claim? Complete parts (a) through (d) below. D. The wind speed in Region A is less than the wind speed in Region B.
Let Region AA be sample 1 and let Region BB be sample 2. Identify H0H_{0} and HaH_{a}. H0:μ1μ2Ha:μ1<μ2\begin{array}{l} H_{0}: \mu_{1} \geq \mu_{2} \\ H_{a}: \mu_{1}<\mu_{2} \end{array} (b) Find the critical value(s) and identify the rejection region.
The critical value(s) is/are z0=z_{0}= \square (Round to two decimal places as needed. Use a comma to separate answers as needed.)

Studdy Solution
For a left-tailed test at α=0.05 \alpha = 0.05 , we need to find the z-score that corresponds to a left-tail area of 0.05.
Looking up this value in a standard normal distribution table, we find:
z0=1.645 z_0 = -1.645
The critical value is:
1.645 \boxed{-1.645}

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