Math

QuestionAn electric range burner weighing 697.0 grams is turned off after reaching a temperature of 455.2C455.2^{\circ} \mathrm{C}, and is allowed to cool down to 23.5C23.5^{\circ} \mathrm{C}.
Calculate the specific heat of the burner if all the heat evolved from the burner is used to heat 586.0\mathbf{5 8 6 . 0} grams of water from 23.5C23.5^{\circ} \mathrm{C} to 80.6C80.6^{\circ} \mathrm{C}.
Answer \square J/gC\mathrm{J} / \mathrm{g}^{\circ} \mathrm{C}

Studdy Solution
The specific heat of the burner is approximately 0.4598 J/gC0.4598 \text{ J/g}^\circ \text{C}.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord