QuestionAn astronaut on the moon throws a baseball upward. The astronaut, is $6 \mathrm{ft}, 6 \mathrm{in}$. tall, and the initial velocity of the ball is 50 ft per sec . The height s of the ball in feet is given by the equation $\mathrm{s}=-2.7 \mathrm{t}^{2}+50 \mathrm{t}+6.5$, where t is the number of seconds after the ball was thrown. Complete parts $a$ and $b$. a. After how many seconds is the ball 20 ft above the moon's surface?
After $\square$ seconds the ball will be 20 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)