Math  /  Probability

Question A wheel has 5 slices numbered 1 to 5, some grey and some white. Find P(X)P(X), the probability the wheel stops on a white slice, and P(not X)P(\text{not }X), the probability it stops on a non-white slice.

Studdy Solution
Fill in the probability of event not XX in the table.
\begin{tabular}{|c|c|c|c|c|c|c|} \hline \multirow{2}{*}{ Event } & \multicolumn{5}{|c|}{ Outcomes } & \multirow{2}{*}{ Probability } \\ \cline { 2 - 6 } & 1 & 2 & 3 & 4 & 5 & \\ \hlineX & \checkmark & & \checkmark & & & P(X)=\frac{2}{5} \\ \hline not X & & \checkmark & & \checkmark & \checkmark & P(\operatorname{not} X)=\frac{3}{5} \\ \hline \end{tabular}
The probabilities for the events are P(X)=25P(X) = \frac{2}{5} and P(not X)=35P(\text{not } X) = \frac{3}{5}.

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