QuestionA volleyball player sets a ball up. Height $h(t) = -16t^2 + 20t + 6$. What is the max height at $t = 0.625$ seconds? A. 8.5 B. 11.625 C. 1225 D. 1.625

Studdy Solution
Re-calculate the value of $h(0.625)$.
$$h(0.625) = -6.25 +12.5 +6 =12.25$$The maximum height of the volleyball is12.25 feet. There seems to be a mistake in the problem or the given options, as none of them match the calculated result. END