QuestionTitrate $0.2121 \mathrm{~g}$ of $\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$ needing $43.31 \mathrm{ml}$ of $\mathrm{KMnO}_{4}$. Find $\mathrm{KMnO}_{4}$ molarity.

Studdy Solution
Calculate the molarity of the $\mathrm{KMn}_{4}$ solution.
$$\text{Molarity of } \mathrm{KMn}_{4} = \frac{0.000633432836 \mathrm{~mol}}{0.04331 \mathrm{}} =0.01463 \mathrm{M}$$The molarity of the $\mathrm{KMn}_{4}$ solution is $0.01463 \mathrm{M}$.